In a Nigerian population, the frequency of males with G6PD deficiency is 0.2. Assuming the
population is in Hardy-Weinberg equilibrium at this locus, what is the frequency of homozygous
females?
/ A. 0.02
/ B. 0.04
/ C. 0.2
/ D. 0.32
/ E. 0.45
Given that q=0.2, so q^2=0.04.
hi calender you considered they are asking homozygous sick female right? what will the answer be if they mean homozygous female nl &sick?
I thought they ask about homozygous mutation at that specific locus, don't they? That means, they are asking about frequency of diseased females.
G6PD is an Xlinked recessive, so male is hemizygous for X chromosome. so male has only one copy of each trait, so the frequency of X linked recessive in males is equal to allel in the population. So q= 0.2 and p = 0.8. female has two copies of each geneon x chromosome, so equation for hardy weinberg equilibrium is same for autosomal traits. in this case homogygous recessive female would occur at a frequency of q square or 0.04.