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Biostat Q - absolutefreaky - Printable Version

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Biostat Q - absolutefreaky - ArchivalUser - 12-07-2008

Drug X- 95% C.I (1.5 to 3.5) Cardiac Index-2.5 L/m2
Drug Y- 95% C.I (0.7 to 2.7) Cardiac Index-1.7 L/m2

P=0.1

What is the likelihood that the difference in the mean cardiac index of the patient receiving Drug X & Y due to chance?
A) 0%
B) 2.5%
C) 5%
D) 7.5%
E) 10%
F) 66.7%
G)95%


0 - ArchivalUser - 12-07-2008

ee


0 - ArchivalUser - 12-07-2008

Please explain how, I banged my head. thx




0 - ArchivalUser - 12-07-2008

i think z Q about type one error when not rejecting z null hypo and assuming a statistically significant when in fact there isn't,z chance of this error is given by z P value 0.1=10%
tell me if am right


0 - ArchivalUser - 12-07-2008

you're right