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+--- Thread: nbme 6 block 4 q 6 - ana01 (/showthread.php?tid=824224)
nbme 6 block 4 q 6 - ana01 - ArchivalUser - 03-22-2016
anybody can explain it? I checked the answer key and seems there is confusion in answers of this question
0 - ArchivalUser - 03-22-2016
Median is (n+1)/2 for odd numbers like here where we have 100 kids, so the middle value of 100 is 50,5th kid
Now look where the 50,5th so to say kid is located on your bar chart n see how many UTI did the kid get
Should be 1...
0 - ArchivalUser - 03-22-2016
sorry i meant even numbers instead of odds.....bloody maths terms lol
0 - ArchivalUser - 03-23-2016
Thank you @littleturtle, Answer 1. When calculatin the median here we have to start counting (to find 50.5) even the children that have 0 infections? This was what l wanted to know. Thanks.
0 - ArchivalUser - 03-23-2016
USMLE STEP-1 16 WEEKS COURSE DETAILS
MORNING AND EVENING GROUPS
4 days a week (Monday through Thursday), each class is of 2 hours
It is a recurring course, can be joined at any point of time
All classes are recorded
Charges: $300/- per month
USMLE STEP-1 4 WEEKS COURSE DETAILS
4 days a week (Sunday through Wednesday), each class is of 2 hours
Next short course will start every month
All classes are recorded
Total charges; $350/-
Thank you USMLE Forum!
Youtube Sample Video Link: https://youtu.be/
0 - ArchivalUser - 03-23-2016
So.....
1----25.5 >>> 0 UTI
26---55.5 >>> 1 UTI
56---65.5 >>> 2 UTI
66---100 >>> 3 UTI
U have to count the kids who had 0 episodes also
0 - ArchivalUser - 03-23-2016
yes it is clear @littleturtle. Thank you very much!