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Kaplan ques-please explain also - ramsha
#1
The reaction catalysed by hepatic phosphofructokinase 1 has a G value of -3.5 kcal/mol. This value indicates that under standard conditions this reaction
A-is reversible
B-occurs very slowly
C-produces an activator of puruvate kinase
D-is inhibited by ATP
E-has a low energy of activation
F-will dec in activity as the ph decreases
G-cannot be used for gluconeogenesis
H-shows cooperative subtrate binding
I-is indirectly inhibited by glucagon
J-is stimulated by fructose 2,6 bisphosphate
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#2
OK ans is G- Now any one can explain why?
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#3
because this value (-3.5 kcal/mol) favors the reaction of the enzyme phosphofructokinase 1 which is an enzyme of glycolysis so it will favor glycolysis and subsequently inhibits gluconeogenesis
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#4
thanks nj_man
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