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General Pharma Q..... - yd

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General Pharma Q..... - yd
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#1
07-17-2010, 04:06 AM
A new antiepileptic drug is being studied. The first test subject is determined to have a volume of distribution of 60 L for this drug and a renal clearance of 4 L/hour. What is the approximate half life of this drug in this patient?
A - 2 hours
B - 7.5 hours
C - 10 hours
D - 15 hours
E - 18 hours
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#2
07-17-2010, 04:12 AM
cc
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#3
07-17-2010, 04:15 AM
t1/2= 0.7*vd/cl
=0.7*60/4
=10
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#4
07-17-2010, 07:14 AM
10.5 CCCCC
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#5
07-17-2010, 07:40 AM
CC...10.5 hours
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#6
07-17-2010, 08:24 AM
Hey u all r right..

t 1/2 = (0.693 x Vd)/Cl. t 1/2 = half life. Vd = volume of distribution. Cl = renal clearance.


Explanation: The equation for half life is t 1/2 = (0.693 x Vd)/Cl . To solve this question you only need to know the equation and plug in the numbers. t ½ = (0.693 x 60L)/(4L/hr) = 10.395 hours or approximately 10 hours.
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