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A new antiepileptic drug is being studied. The first test subject is determined to have a volume of distribution of 60 L for this drug and a renal clearance of 4 L/hour. What is the approximate half life of this drug in this patient?
A - 2 hours
B - 7.5 hours
C - 10 hours
D - 15 hours
E - 18 hours
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t1/2= 0.7*vd/cl
=0.7*60/4
=10
cc
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Hey u all r right..
t 1/2 = (0.693 x Vd)/Cl. t 1/2 = half life. Vd = volume of distribution. Cl = renal clearance.
Explanation: The equation for half life is t 1/2 = (0.693 x Vd)/Cl . To solve this question you only need to know the equation and plug in the numbers. t ½ = (0.693 x 60L)/(4L/hr) = 10.395 hours or approximately 10 hours.