Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
q5! - sarim
#1
A man is a known heterozygous carrier of a mutation causing hyperprolinemia, an autosomal recessive condition. Phenotypic expression is variable and ranges from high urinary excretion of proline to neurologic manifestations including seizure. Suppose that 1/40,000 of the population is homozygous for the mutation causing this condition. If the man mates with somebody from the general population, what is the probability that he and his mate will produce a child who is homozygous for the mutation involved ?

A-1/100
B-1/200
C-1/400
D-1/1000
E-1/2000
Reply
#2
CC
Reply
#3
cc
Reply
#4
Smile
Reply
#5
CCC

gene freq=1/200

chance of female being a carrier= 2pq= 2*1*1/200= 1/100

chance of her transmission of mutant allele = 1/2

chance of male transmission of mutant allele= 1/2

so chance of child with mutant allele= 1/100 * 1/2 * 1/2 = 1/400
Reply
#6
redceo thanks for the explanation,
Reply
« Next Oldest | Next Newest »


Forum Jump: