E is my ans? pls. explain if i am wrong - angela64

[ArchivalUser]

Two experimental drugs, drug X and drug Y, are being evaluated for treatment of congestive heart failure. Patients receiving drug X have a cardiac index of 2.5 L/m2 with a 95% confidence interval of 1.5 to 3.5. Patients receiving drug Y have a cardiac index of 1.7 L/m2 with a 95% confidence interval of 0.7 to 2.7. A test of the significance of difference shows a p-value of 0.1. Which of the following is the likelihood that the difference in mean cardiac index of patients receiving drug X and drug Y is due to chance?

A. 0%
B. 2.5%
C. 5%
D. 7.5%
E. 10%
F. 66.7%
G. 95%

[ArchivalUser]

How can we explain, when you never explain these answers you choose
also where are all these questions from btw?

[ArchivalUser]

These questions are just to confuse ppl and to spread spam !! So just don't bother answering these questions . @faith16

[ArchivalUser]

http://www.usmleforum.com/showthread.php?tid=839463. Check this out