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A 13-year-old female presents with her mother requesting information about the mechanism by which human papillomavirus (HPV) increases the risk of cervical carcinoma. Which of the following statements is true regarding HPV-associated cervical carcinoma?
A. E6 activates E2F-mediated transcription
B. E7 inhibits E2F-mediated transcription
C. E6 activates the retinoblastoma (Rb) gene product
D. E7 inhibits the retinoblastoma (Rb) gene product
E. E6 activates the tumor suppressor p53
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i am sorry - i meant to mark D.
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D
E6 and E7 that INACTIVATE p53 and Rb tumor suppressor genes, are asso with HPV associated cervical carcinoma.
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D is the correct answer
The carcinogenic effects of HPV types 16 and 18 are primarily associated with viral antigens E6 and E7. E6 promotes cervical carcinoma through inhibition of the tumor suppressor p53. E7 does so via inhibition of the retinoblastoma (Rb) gene product, which disinhibits E2F and promotes transcription and cell proliferation.
E6 does not influence E2F-mediated transcription (A); rather, E6 works by inhibiting p53.
E7 activates E2F-mediated transcription as described above; it does not inhibit it (B).
E6 does not activate the Rb gene product ©; rather, it inhibits p53.
E6 inhibits p53; activation of p53 (E) would decrease the risk of carcinoma, it would not promote carcinogenicity.
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When does P53 is activated in a normal cell ?
