Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
beh.sci - kebi
#1
A father comes to you, asking what percentage chance is there that his baby will have schizophrenia if the following is known
- He does not have schizophrenia, nor does anyone in his family, His wife is 29 years old & she has a monozygotic twin with schizophrenia. She however does not have schizophrenia.

What is the chance that their child will have schizophrenia
a. 1%
b. 10 %
c. 50 %
d. 99%
Reply
#2
Do we measure it by the heritability index?
It should be:
47% In monozygotic twins
13% in dizygotic twins
HI = MZ-DZ/ 100-DZ

Roughly around 40% ....

Is C) the answer?
Reply
#3
I think the answer is B 10% due to risk in biologic relative (mom's MZ twin sis). Pt's mother is certainly at risk herself 47% but at the time is not schizo.
Reply
#4
I think it is B too.
Risk in biologic relatives 10%
If 1 parent or 1 sibling 12%
So I'll go with B.
Reply
#5
i think its b too coz its 10% risk if one of ur uncle or aunt has it..no.correct me if i am wrong
Reply
« Next Oldest | Next Newest »


Forum Jump: