08-17-2006, 05:58 PM
An Rh-negative woman married to a heterozygous Rh-positive man has three children. The probability that all three of their children are Rh-positive is
a) 1:2
b) 1:4
a) 1:2
b) 1:4
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genetic 2 - pth
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08-17-2006, 07:18 PM
answer is A
rh -ve geniotype is aa and heterozygous rh +ve is Aa so combinations are aa,aA,Aa,aa so 1/2chance of being rh+ve for their each children.
08-17-2006, 08:08 PM
well rh is codominant so there is 1/2 chance for each child to b rh + ,but the chance of all the three,since each event is indepent would b 1/2x1/2 x1/2=1/8 however this is not in choice . can somebody give their opinion??
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