04-07-2010, 05:07 AM
Can anyone help explain for me please questions 4, 15 and 16?
Thanks
Thanks
NMBE 3 block 1...goforward, iqbalian, sammy, any1? - ia
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04-07-2010, 05:07 AM
Can anyone help explain for me please questions 4, 15 and 16?
Thanks
04-07-2010, 07:07 AM
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04-07-2010, 09:09 AM
4 :. From the graph it is apparent that the cell has been placed in a hypotonic solution. Remember that one millimole of NaCl has '2' osmotically active particles. So one millimole of NaCl = 2msom/L. There is only one value in the options that if doubled ( to get the value in mOsm/L) remains lesser than 300mSom/L ( the osmolarity of plasma). This value is 75 obviously. For the next small value of 150, the mOsm becomes 300..which is isotonic with plasma, not hypo.
15:. They say the locus is present on Y chromosomes. So it must be in the male mouse. The recepient offspring is A x B by genome. So he or she must have the Y chromosome and the mentioned allele. If he has to be genetically complimented by the donor, the donor has to carry the allele of Y chromosome. That is only possible if it receives the transplant from the "MALE" mouse product of A x B cross. 16. this is about arranging the values in the 2x2 table.. I did it like this Positive PPD.............Negative PPD.. 1...............................1___________> Tuberculus 99..............................9999________> Non tuberculous _________________________ 100.............................10,000 so by formula..RR = incidence in PPD positive patients/ Incidence in PPD negative patients This becomes 1/100 divided by 1/10,000. or 10,000/100= 100..
04-07-2010, 09:18 AM
Sammy, thank you so much
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