10-24-2007, 08:14 AM
A)There are 40 total alleles of the 20 people of which 2 alleles are cystic fibrous causing.
2/40 = .05 the f of the cystic fibrous allele
thus cc or q2 = (.05)2 =.0025 or .25% of the population will be born with cystic fibrous.
B) 0.25/.059 = about 4 times greater occurrence
2/40 = .05 the f of the cystic fibrous allele
thus cc or q2 = (.05)2 =.0025 or .25% of the population will be born with cystic fibrous.
B) 0.25/.059 = about 4 times greater occurrence