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The base sequence of codons 57-58 in the chromosome beta 5 reductase gene is CAGCGC. The mRNA produced upon transcription of this gene will contain the sequence:
A. GCGCTG
B. CUGCGC
C. GCGCUG
D. CAGCGC
E. GUCGCG
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aaa/.....jus do antiparallel n complementary
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m RNA is antiparalell and complementary to templet not to codon.
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the answer according to kaplan is D but how can we say that.
i mean they didnt give whether it is template or coding strand
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vlsr read the question aqain it stated very clearly that it is codon.
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base sequences conveniently written in 5' ---3' direction
beta 5 reductase gene is CAGCGC
5' CAGCGC 3'
anti parallel mRNA 3'GUCGCG 5'
it should be written as 5'GCGCUG 3'
GCGCUG
answer is CCC
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i just dont get one thing ananth, how come u get 380 or whatever? it doesnt make sense.