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Tay Sacks and Sandhof ds are mutations on the alpha and beta sub units of B-hexosaminidase enz. respctively. If a carrier of Tay Sacks ds marries a carrier of Sandhof ds, what is the probability that their 1st child will have either ds?
a, 0%
b, 12.5%
c, 25%
d, 50%
e, 100%
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this q is from kaplan q bank no??
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Actually the Q'n is not from Kaplan.
Can anybody explain for me please?
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they're recessive, that means that only if two parents are carriers (or diseased) for the SAME muation, the child will inherit the DISEASE. since these are two separate diseases on 2 different sites on the chromosomes, the mutant gene for alpha is present only on one parent, the mutant gene for beta is present only on one parent. so the child will inherit 1 alpha mutation, and 1 beta mutation, and will be a carrier for both diseases, but will not have either one of the diseases...