Bio....2Q - maryam2009 - Printable Version +- USMLE Forum - Largest USMLE Community (https://www.usmleforum.com) +-- Forum: USMLE Forum (https://www.usmleforum.com/forumdisplay.php?fid=1) +--- Forum: Step 1 (https://www.usmleforum.com/forumdisplay.php?fid=2) +--- Thread: Bio....2Q - maryam2009 (/showthread.php?tid=646608) Pages:
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Bio....2Q - maryam2009 - ArchivalUser - 01-13-2012 Consider a reaction that can be catalized by one of two enzymes,A and B,with the following kinetics .....................Km(M).................Vmax(mmol/min) A...................5*10^-6...............20 B...................5*10^-4...............30 At a concentration of 5*10^-4 M substrate,the velocity of the reaction catlized by enzyme A will be: A.10 B.15 C.20 D.25 E.30 please explain your answer.Thank you 0 - ArchivalUser - 01-13-2012 ans, C, I think v max doesnot change with sub con 0 - ArchivalUser - 01-13-2012 v=v max[s]/Km+[s] c is ans 0 - ArchivalUser - 01-13-2012 Agree with CC........ 0 - ArchivalUser - 01-13-2012 the answer is C As dr_eurekha mentioned ....the Vmax depends on Number of the enzymes and absolutely unrelated to Substrate concentrations....at the concentration 5*10^-4 ,enzyme A works at its Vmax,which is 20 mmol/min. Thank you 0 - ArchivalUser - 01-13-2012 And you 0 - ArchivalUser - 01-22-2012 Hello, Because I am a little confused, could you please help me understand the question? Does it ask about the velocity of the reaction or the Vmax of the reaction? Thank you so much, Elpida 0 - ArchivalUser - 01-22-2012 Vmax is the maximum velocity or rate at which the enzyme catalyzed a reaction...and it depends only on Number of the enzymes not substate concentrations,so increased or decreased [substreaes] will not change the amount of Vmax ....so in this case at the new concentration (5*10^-4) ,enzyme A works at its Vmax,which is 20 mmol/min. . 0 - ArchivalUser - 01-22-2012 Vmax is the maximum velocity or rate at which the enzyme catalyzed a reaction...and it depends only on Number of the enzymes not *substrate concentrations,so increased or decreased* [substrates] will not change the amount of Vmax ....so in this case at the new concentration (5*10^-4) ,enzyme A works at its Vmax,which is 20 mmol/min. 0 - ArchivalUser - 01-23-2012 Thank you so much for your explanation. Is the substrate concentration power to -4 or power to 4? Thank you again, I appreciate your help |