Biostat Q - absolutefreaky

[ArchivalUser]

Drug X- 95% C.I (1.5 to 3.5) Cardiac Index-2.5 L/m2
Drug Y- 95% C.I (0.7 to 2.7) Cardiac Index-1.7 L/m2

P=0.1

What is the likelihood that the difference in the mean cardiac index of the patient receiving Drug X & Y due to chance?
A) 0%
B) 2.5%
C) 5%
D) 7.5%
E) 10%
F) 66.7%
G)95%

[ArchivalUser]

ee

[ArchivalUser]

Please explain how, I banged my head. thx

[ArchivalUser]

i think z Q about type one error when not rejecting z null hypo and assuming a statistically significant when in fact there isn't,z chance of this error is given by z P value 0.1=10%
tell me if am right

[ArchivalUser]

you're right