03-22-2016, 06:09 PM
anybody can explain it? I checked the answer key and seems there is confusion in answers of this question
nbme 6 block 4 q 6 - ana01
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03-22-2016, 06:09 PM
anybody can explain it? I checked the answer key and seems there is confusion in answers of this question
03-22-2016, 11:44 PM
Median is (n+1)/2 for odd numbers like here where we have 100 kids, so the middle value of 100 is 50,5th kid
Now look where the 50,5th so to say kid is located on your bar chart n see how many UTI did the kid get Should be 1...
03-22-2016, 11:54 PM
sorry i meant even numbers instead of odds.....bloody maths terms lol
03-23-2016, 08:49 AM
Thank you @littleturtle, Answer 1. When calculatin the median here we have to start counting (to find 50.5) even the children that have 0 infections? This was what l wanted to know. Thanks.
03-23-2016, 08:52 AM
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03-23-2016, 09:20 AM
So.....
1----25.5 >>> 0 UTI 26---55.5 >>> 1 UTI 56---65.5 >>> 2 UTI 66---100 >>> 3 UTI U have to count the kids who had 0 episodes also
03-23-2016, 09:58 AM
yes it is clear @littleturtle. Thank you very much!
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